Question

Calculate the binding energy per nuclear of Li isotope, which has the isotopic mass of 7.16 $m_u$. The individual masses of neutron and proton are 1.008665 $m_u$ and 1.007277 $m_u$, respectively and the mass of electron = 0.000548 $m_u$.

• A. 5.604 MeV/nucleon
• B. 8.674 MeV/nucleon
• C. 6.204 MeV/nucleon
• D. None of these

Answer 1

Answer: (A)

5.604 MeV/nucleon

Mass defect $=7.16-(4\times 1.008665+3\times 1.007277+3\times 0.000548)$
$=7.016-7.058135$
$=-0.042135units$

$\therefore BE=0.042135\times 931MeV=39.228MeV$

$\therefore BEpernucleon=\left(\frac{BE}{7}\right)=5.604MeV/nucleon$