Question

Calculate the boiling point of the liquid if its entropy of vaporization is $110J{K}^{-1}{mol}^{-1}$ and the enthalpy of vaporization is $40.85kJ{mol}^{-1}$.

• A. $371.36K$
• B. $271.36K$
• C. $471.36K$
• D. $0K$

Answer 1

The correct option is A $371.36K$

We have,

$T=\frac{\Delta H}{\Delta S}$

$T=\frac{40850}{110}K=371.36K$