Calculate the bond energy of Cl-Cl bond from the following data- CH4g-Clg- CH3Clg-HClg- - H-100-3 kJ- Also the bond enthalpies of C-H-C-Cl-H-Cl bonds are 413-326 and 431 kJmol-1 respectively-

Given BE_C H=413 kJ; BE_H Cl=413 kJ Hr = ∑ H_product ∑_reactant Hr = 3(C H)+(C Cl)+(H Cl) 4(C H) (Cl Cl) Putting values of given bond enthal ...

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Enthalpy

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Calculate the bond energy of $C l - C l$ bond from the following data:
$C H_{4 (g)} + C l_{(g)} \to C H_{3} C l_{(g)} + H C l_{(g)}; Δ H = - 100.3 k J$ . Also the bond enthalpies of $C - H, C - C l, H - C l$ bonds are $413, 326$ and $431$ $k J m o l^{- 1}$ respectively.

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C - C l

C H_{3} C l (g) + {C l}_{2} (g) ⟶ C H_{2} {C l}_{2} (g) + H C l (g)

Δ H^{o} = - 104 k J

C - H

C l - C l

H - C l

414

243

431 k J {m o l}^{- 1}

C H_{4} (g) + C l_{2} \to C H_{3} C l (g) + H C l (g)

δ H = - 25 k c a l .

C l - C l

x : y = 9 : 5

Δ H

- 25 k c a l

C H_{4} (g) + C l_{2} (g) \to C H_{3} C l (g) + H C l (g)

C l - C l

H - H, C l - C l

H - C l

435, 243

431

m o l^{- 1}

H C l (g)

△

H - H | C | C l - C l (g) ⟶ C (s) + 2 H (g) + 2 C l (g)

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