Calculate the cell EMF in mV for : Pt|H2(1atm)|HCl(0.01M)|AgCl(s)|Ag(s)at298K if ΔGot values are at 25oC −109.56kJmol for AgCl(s) and −130.79kJmol for (H+ + Cl−) (aq)
A
456mV
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
654mV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
546mV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A456mV (H2+2AgCl→2Ag+2H++2Cl− ΔG0cellreaction=2(−130.79)−2(−109.56)=−42.46kJ/mole=−2f×E0cell ∴E0cell=−42460−2×96500=+0.220V Now, Ecell=+0.220+0.0592log1(0.01)4=0.456V=456mV