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Third Law of Thermodynamics

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Question

Calculate the change in entropy when $1$ mole nitrogen gas expands isothermally and reversibly from an initial volume of $1$ litre to a final volume of $10$ litre at $27^{o} C$ .

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Solution

$Δ S = 2.303 n R log (\frac{V_{2}}{V_{1}})$
$= 2.303 \times 1 \times 8.314 log (\frac{10}{1}) = 19.12 J K^{- 1}$

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