Question

Calculate the change in momentum of a car of mass 1000 Kg when it's speed increases from 36 Km/h to 108 Km/h uniformly?

Answer 1

Given that,

Mass $m=1000kg$

Speed $v_1=36km/h=10m/s$

Speed $v_2=108km/h=30m/s$

We know that,

The change in momentum

$\Delta P=m\left(\Delta v\right)$

$\Delta P=m\times (v_2-v_1)$

$\Delta P=1000\times (30-10)$

$\Delta P=2\times {10}^{4}kgm/s$

Hence, the change in momentum is $2\times {10}^{4}kgm/s$