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Calculate the...

Question

Calculate the change in the value of $g$ at altitude $45$ . Take radius of earth $= 6.37 \times 10^{3} k m$

- 0.064 m / s^{2}

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- 0.0168 m / s^{2}

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- 0.0232 m / s^{2}

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- 0.0548 m / s^{2}

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Solution

The correct option is B $- 0.0168 m / s^{2}$
$Δ g = g^{'} - g = - R ω^{2} {cos}^{2} θ$
$= - (6.37 \times 10^{6}) {(\frac{2 π}{24 \times 3600})}^{2} {cos}^{2} 45^{\circ}$
$= - 0.0168 m / s^{2}$

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Calculate the change in the value of g at altitude 45. Take radius of earth =6.37×103km

The correct option is B −0.0168m/s2Δg=g′−g=−Rω2cos2θ=−(6.37×106)(2π24×3600)2cos245∘=−0.0168m/s2

Calculate the change in the value of $g$ at altitude $45$ . Take radius of earth $= 6.37 \times 10^{3} k m$

The correct option is B $- 0.0168 m / s^{2}$
$Δ g = g^{'} - g = - R ω^{2} {cos}^{2} θ$
$= - (6.37 \times 10^{6}) {(\frac{2 π}{24 \times 3600})}^{2} {cos}^{2} 45^{\circ}$
$= - 0.0168 m / s^{2}$