Calculate the coefficient of variation of the following data: $40, 36, 64, 48, 52$

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Solution

$\frac{\sum x}{N} = \frac{240}{5} = 48$

${(x_{i} - μ)}^{2} = 64, 144, 256, 0, 16$
$\sum {F (x_{i} - μ)}^{2} = 480$
$σ = \sqrt{\frac{\sum {(x_{i} - μ)}^{2}}{n - 1}} = \sqrt{\frac{480}{4}} = 10.954$
$C V = \frac{10.954 \times 100}{48} = 22.82$

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Calculate the coefficient of variation of the following data: 40,36,64,48,52

∑xN=2405=48(xi−μ)2=64,144,256,0,16∑F(xi−μ)2=480σ=√∑(xi−μ)2n−1=√4804=10.954CV=10.954×10048=22.82

Calculate the coefficient of variation of the following data: $40, 36, 64, 48, 52$

$\frac{\sum x}{N} = \frac{240}{5} = 48$

${(x_{i} - μ)}^{2} = 64, 144, 256, 0, 16$
$\sum {F (x_{i} - μ)}^{2} = 480$
$σ = \sqrt{\frac{\sum {(x_{i} - μ)}^{2}}{n - 1}} = \sqrt{\frac{480}{4}} = 10.954$
$C V = \frac{10.954 \times 100}{48} = 22.82$