Calculate the combined correction for curvature and refraction (in m) for a distance of 2 km.

0.269

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0.045

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3.14

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0.135

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Solution

The correct option is A 0.269
The correction due to the curvature of the earth and the refraction can be combined into one composite correction, i.e., combined correction (C).

$C = C_{c} + C_{r}$

$= - 0.0785 d^{2} + 0.0112 d^{2}$

$C = - 0.0673 d^{2}$

Remember

where C is in meters and d is in kilometers
$C_{c}$ is curvature correction

$C_{r}$ is refraction correction

d = Horizontal distance between two points of the earth surface = 2 km

$C o m b i n e d c o r r e c t i o n, C = - 0.0673 \times 2^{2} = - 0.2692 m$

Suggest Corrections

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