Calculate the compound interest on ₹ 15000 in 3 years; if the rates of interest for successive years be 6%, 8% and 10% respectively.

₹ 3789.20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

₹ 3889.20

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

₹ 4389.20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

₹ 3684.20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
₹ 3889.20

Principal(P)=₹ 15000
Time(t)=3 years
Rate( $R_{1}$ )= 6%
Rate( $R_{2}$ )= 8%
Rate( $R_{3}$ )=10%
Amount= $P (1 + \frac{R_{1}}{100}) (1 + \frac{R_{2}}{100}) (1 + \frac{R_{3}}{100})$
$= ₹ 15000 \times (1 + \frac{6}{100}) (1 + \frac{8}{100}) (1 + \frac{10}{100})$
$= ₹ 15000 \times \frac{53}{50} \times \frac{27}{25} \times \frac{11}{10} = ₹ 18889.20$
C.I.=Amount-Principal
= ₹ 18889.20- ₹ 15000= ₹ 3889.20

Suggest Corrections

Similar questions

Calculate the compound interest on $R s . 15000$ in $3$ years; if the rates of interest for successive years be $6 %$ , $8 %$ and $10 %$ respectively.

Calculate the compound interest accrued on Rs. 6,000 in 3 years, compounded yearly, if the rates for the successive years are 5%, 8% and 10% respectively.

Join BYJU'S Learning Program

Calculate the compound interest on ₹ 15000 in 3 years; if the rates of interest for successive years be 6%, 8% and 10% respectively.

The correct option is B ₹ 3889.20 Principal(P)=₹ 15000 Time(t)=3 years Rate(R1)= 6% Rate(R2)= 8% Rate(R3)=10% Amount= P(1+R1100)(1+R2100)(1+R3100) =₹15000×(1+6100)(1+8100)(1+10100) =₹15000×5350×2725×1110=₹18889.20 C.I.=Amount-Principal = ₹ 18889.20- ₹ 15000= ₹ 3889.20