Calculate the compound interest on $Rs. 3, 500$ at $10 %$ per annum in $2$ years.

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Solution

Given:
$P = Rs. 3500$
$R = 10 %$
$t = 2$ years

$\begin{matrix} A & = P {(1 + \frac{R}{100})}^{n} = 3500 {(1 + \frac{10}{100})}^{2} = 3500 {(1.1)}^{2} = Rs. 4235 \end{matrix}$

So, compound interest will be,
$A - P = 4235 - 3500$
$= Rs. 735$

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Calculate the compound interest on Rs. 3,500 at 10% per annum in 2 years.

Given:P=Rs. 3500R=10%t=2 yearsA=P(1+R100)n=3500(1+10100)2=3500(1.1)2=Rs. 4235So, compound interest will be,A−P=4235−3500 =Rs. 735

Calculate the compound interest on $Rs. 3, 500$ at $10 %$ per annum in $2$ years.

Given:
$P = Rs. 3500$
$R = 10 %$
$t = 2$ years

$\begin{matrix} A & = P {(1 + \frac{R}{100})}^{n} = 3500 {(1 + \frac{10}{100})}^{2} = 3500 {(1.1)}^{2} = Rs. 4235 \end{matrix}$

So, compound interest will be,
$A - P = 4235 - 3500$
$= Rs. 735$