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Question

Calculate the concentration of electrolyte (C1) at anode for the given cell:

Ag(s)|AgNO3(aq, C1 M)||AgNO3(aq, C2=0.2 M)|Ag(s)

The emf of the cell is 0.8 V

Take
Antilog (13.5)=3.16×1013

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Solution

Ag(s)|AgNO3(aq, C1 M)||AgNO3(aq, C2=0.2 M)|Ag(s)

For the given cell representation, the cell reaction will be,
Ag+(aq, C2=0.2 M)Ag+(aq, C1 M)

For concentration cell, we know that,
Ecell=E0cell0.0591nlog[C1][C2]

Ecell=E0cell+0.0591nlog[C2][C1]

For concentration cells, cathode and anode consist of same metal and its solution​.
Thus,
E0=0

0.8=0.05911log [0.2][C1]

0.80.0591=log [0.2]C1

13.5log [0.2]C1

Antilog (13.5)=0.2C1

3.16×1013=0.2C1

C1=0.063×1013M

C1=0.63×1014M


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