Question

Calculate the concentration of $HCl$ acid if $50ml$ of $HCl$ is required to neutralize $25ml$ of $1MNaOH$ in acid base titration.

• A. $0.25M$
• B. $0.5M$
• C. $1.0M$
• D. $1.5M$

Answer 1

The correct option is B $0.5M$

$HCl+NaOH\to NaCl+H_{2}O$

In this chemical reaction, the molar ratio is $1:1$ between $HCl$ and $NaOH$.

So, moles of $HCl$ = moles of $NaOH$

$M_{HCl}\times$ Volume of $HCl$ = $M_{NaOH}\times$ Volume of $NaOH$

$M_{HCl}=\frac{M_{NaOH}\times volumeofNaOH}{volumeofHCl}$

$M_{HCl}=\frac{25.00ml\times 1.00M}{50.00ml}$

$M_{HCl}=0.50MHCl$

So, the concentration of $HCl$ is $0.50M$.