Calculate the couple on a car's steering wheel of diameters 40 cm. The force applied on each side is 2N.

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Solution

Step 1: Give data,
The diameter of the wheel is $= 0.4 m$
The force acting on each side is $= 2 N$
Step 2: Calculating the couple acting,
$C o u p l e = D i s \tan c e x F o r c e C o u p l e = 0.4 x 2 = 0.8 N m$
The couple acting in the given case is $0.8 N m$ .

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Calculate the couple on a car's steering wheel of diameters 40 cm. The force applied on each side is 2N.

Step 1: Give data,The diameter of the wheel is =0.4mThe force acting on each side is =2NStep 2: Calculating the couple acting,Couple=DistancexForceCouple=0.4x2=0.8NmThe couple acting in the given case is 0.8Nm.

Step 1: Give data,
The diameter of the wheel is $= 0.4 m$
The force acting on each side is $= 2 N$
Step 2: Calculating the couple acting,
$C o u p l e = D i s \tan c e x F o r c e C o u p l e = 0.4 x 2 = 0.8 N m$
The couple acting in the given case is $0.8 N m$ .