Calculate the critical angle for glass-air interface if a ray of light incident on a glass surface is deviated through $15^{0}$ when angle of incidence is $45^{0}$

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Solution

Given,

$i = 45$

$r = 45 - 15 = 30$

$sin i_{c} = \frac{sin 30}{sin 45} = 0.707$

$i_{c} = {sin}^{- 1} (0.707) = {44.99}^{\circ}$

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Calculate the critical angle for glass-air interface if a ray of light incident on a glass surface is deviated through 150 when angle of incidence is 450

Given,i=45r=45−15=30sinic=sin30sin45=0.707ic=sin−1(0.707)=44.99∘

Calculate the critical angle for glass-air interface if a ray of light incident on a glass surface is deviated through $15^{0}$ when angle of incidence is $45^{0}$

Given,

$i = 45$

$r = 45 - 15 = 30$

$sin i_{c} = \frac{sin 30}{sin 45} = 0.707$

$i_{c} = {sin}^{- 1} (0.707) = {44.99}^{\circ}$