Calculate the critical constants of a gas whose van der Waals constants A and b are 0.751L²atm mol^-2 and 0.0225Lmol^-1

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Solution

Vc = 3b = 3 X 0.0225 = 0.0675 L

Pc = a/27b²= 0.751/27 (0.0225)² = 54.94 atm

Tc = 8a/27bR = (8 X 0.751)/(27 X 0.0225 X 0.0821) = 6.008/ 0.0499 = 120.46 K

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