Question

Calculate the current flowing through the resistance $2\Omega$

Answer 1

The given circuit is forming a balanced wheat-stone bridge.

The equivalent resistance of the circuit will be given by:

$10\Omega \&2\Omega$ are in series and $25\Omega \&5\Omega$ are in series.

Equivalent for $10\Omega \&2\Omega$

$R_{e1}=12\Omega$

Equivalent for $25\Omega \&5\Omega$

$R_{e2}=30\Omega$

Total Equivalent $R_e$

$\frac{1}{R_e}=\frac{1}{12}+\frac{1}{30}{R}_e=\frac{60}{7}$

Also:

$i_1{R}_{e1}=i_2{R}_{e2}$

$\frac{i_1}{i_2}=\frac{5}{2}$

Thus, the current will be divided in the circuit in ratio of5:2

Thus, the current in $R_{e1}$ will be

$i_1=\frac{1.4\times 5}{7}=1A$

Thus the current in 2 ohm resistance nwill be 1 A.