Question

Calculate the current strength which was passed for 15 min to liberated $193.11c{m}^3$ of hydrogen gas at $273K$ and $760mm$ of $Hg$ pressure during electrolysis of acidulated water.

Answer 1

${2H}^{+}+2e^{-}⟶H_2$

we know, ideal gas equation,

$PV=nRT$

$n=\frac{1\times 193.11}{0.0821\times 273}$

$n=0.00861mol$

$\therefore$ Faraday $=2\times 0.00861F=\frac{change}{96500}$

$1661.73=I\times 15\times 60$

$I=1.85A$