Calculate the curved surface area of a frustum cone given below :

125.6

i n^{2}

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225.6

i n^{2}

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325.6

i n^{2}

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425.6

i n^{2}

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Solution

The correct option is A 125.6 $i n^{2}$
Curved surface area = $π (R + r) l$
= $π (3 + 1) \times 10$
= $3.14 \times 4 \times 10$
= 125.6 $i n^{2}$

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Calculate the curved surface area of a frustum cone given below :

The correct option is A 125.6 in2Curved surface area = π(R+r)l= π(3+1)×10= 3.14×4×10= 125.6 in2

The correct option is A 125.6 $i n^{2}$
Curved surface area = $π (R + r) l$
= $π (3 + 1) \times 10$
= $3.14 \times 4 \times 10$
= 125.6 $i n^{2}$