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Question

Calculate the de Broglie wavelength of an electron having kinetic energy of 1.6×106erg (me=9.11×1028g,h=6.62×1027ergsec).

A
90Ao
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B
0.00029Ao
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C
0.0122Ao
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D
1.29Ao
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Solution

The correct option is B 0.0122Ao
The expression for the kinetic energy E is E=12mu2
Hence, u=2Em......(1)
The De-broglie equation is λ=hmu.....(2)
Substittue (2) in (1)
λ=h2mE
Substitute values in the above expression.
λ=6.62×10272×9.11×1028×1.6×106=1.226×1010cm=0.01226Ao
Hence, the de Broglie wavelength of the electron is 0.01226Ao

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