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Question

# Calculate the degree of hydrolysis (h) of a salt of aniline and acetic acid in 0.1 M solution at 25∘C Given : Ka for CH3COOH is 1.8×10−5 Kb for aniline is 4.6×10−10

A
0.996
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B
0.235
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C
0.85
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D
0.523
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Solution

## The correct option is D 0.523Since aniline and acetic acid are both weak electrolytes. So, Kh=KwKa×KbKh=10−141.8×10−5×4.6×10−10=1.2 if we see, KhC=1.20.1=12 Since, KhC<100, So we cannot take the approximation 1−h≈1 and we have to solve quadratic, Kh=h2(1−h)2√Kh=h1−h√1.2=h1−h1.096=h1−hh=1.0962.096=0.523

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