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Question

Calculate the degree of ionization and [H3O+] of 0.01MCH3COOH solution. The equilibrium constant of acetic acid is 1.8×105.

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Solution

Given, K=1.8×105,C=0.01M

We know that K=Cα2

So 18×106=102α2

18×106=α2

α=18×102=32×102

α=4.2×102

α=0.042

Hence , degree of ionization is 0.042

[H+]=Cα=0.01(0.042)

[H+]=42×105 M


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