Calculate the - Go and equilibrium constant of the reaction at 27-C Mg-C u -2 - M g -2 -Cu E Mg 2- - Mg -2-37V- E Cu 2- - Cu -0-34V

(i) E_Mg^2+/Mg= 2.37V ⇒ E_Cu^2+/Cu=0.34V E^o=E_R E_L=0.34 ( 2.37)=2.71V (ii) Δ G^o=nFE^o #160; #160; #160; #160; #160; #1 ...

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Byju's Answer

Standard XII

Chemistry

Arrhenius Equation

Calculate the...

Question

Calculate the $Δ G^{o}$ and equilibrium constant of the reaction at $27^{\circ} C$
$M g + C u^{+ 2} ⇌ M g^{+ 2} + C u$
$E_{{M g}^{2 +} / M g} = - 2.37 V;$
$E_{{C u}^{2 +} / C u} = 0.34 V$

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Solution

(i) $E_{M g^{2 +} / M g} = - 2.37 V$
$\Rightarrow E_{C u^{2 +} / C u} = 0.34 V$
$E^{o} = E_{R} - E_{L} = 0.34 - (- 2.37) = 2.71 V$

(ii) $Δ G^{o} = n F E^{o}$
$= 2 \times 96500 C m o l^{- 1} \times 2.71 V$ ... [ $n = 2$ because $2$ electrons involved]
$= 523030 J$ ... $(C \times V = J o u l e)$
$= 523.030 K J$

(iii) $log K = \frac{n F E^{o}}{2.303 R T} = \frac{523030 J}{2.303 \times 8.314 J K^{- 1} m o l^{- 1} \times 300 K}$
$= 91.05$
$\Rightarrow log K = 91.05$
$\Rightarrow K$ = Antilog $(91.05) = 1.13 \times 10^{91}$ .

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Calculate the ΔGo and equilibrium constant of the reaction at 27∘CMg+Cu+2⇌Mg+2+CuEMg2+/Mg=−2.37V;ECu2+/Cu=0.34V

Calculate the $Δ G^{o}$ and equilibrium constant of the reaction at $27^{\circ} C$
$M g + C u^{+ 2} ⇌ M g^{+ 2} + C u$
$E_{{M g}^{2 +} / M g} = - 2.37 V;$
$E_{{C u}^{2 +} / C u} = 0.34 V$