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Question

Calculate, the ΔGo at 85 oC for the reaction:
Fe2O3(s)+3H2(g)2Fe(s)+3H2O
The data are: ΔHo298=35 kJ/mol
ΔSo358=0.095 kJmol1K1
Substance Fe2O3(s) Fe(s) H2O(l) H2(g)
Cop (JK1mol1) 103 25 75 29

A
4.11 kJmol1
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B
63.91 kJmol1
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C
63.91 kJmol1
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D
4.11 kJmol1
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Solution

The correct option is B 63.91 kJmol1
Given,
Fe2O3(s)+3H2(g)2Fe(s)+3H2O
We know, ΔCop=(Cp)P(Cp)R
ΔCp=2×25+3×751033×29=85 J/molK

Again, ΔHT2ΔHT1T2T1=ΔCp
ΔH358(35)358298=85×103
ΔHo358=29.9 kJmol1

We know, ΔGo=ΔHoTΔSo
=29.9358×0.095 =63.91 kJmol1

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