Calculate the - H r of KHs-

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Standard XII

Chemistry

First Law of Thermodynamics

Calculate the...

Question

Calculate the ${Δ H}_{r}$ of KH(s).

62 kJ/mol

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124 kJ/mol

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31 kJ/mol

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None of these

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Solution

The correct option is A 62 kJ/mol
Born-Haber Cycle
It is a series of steps (chemical processes) used to calculate the lattice energy of ionic solids, which is difficult to determine experimentally. You can think of BH cycle as a special case of Hess's law which states that the overall energy change in a chemical process can be calculated by breaking down the process into several steps and adding the energy change from each step.

$({Δ H}_{f})_{K H}$ = - $\frac{124}{2} \Rightarrow$ 62 kJ/mole.

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Similar questions

Q. The Born Haber cycle below represents the energy changes occurring at 298K when

K H

is formed from its elements
v :

{Δ H}_{a t o m i s a t i o n}

K = 90 k J / m o l

w :

{Δ H}_{i o n i s a t i o n}

K = 418 k J / m o l

x :

{Δ H}_{d i s s o c i a t i o n}

H = 436 k J / m o l

y :

{Δ H}_{e l e c t r o n a f f i n i t y}

H = 78 k J / m o l

z :

{Δ H}_{l a t t i c e}

K H = 710 k J / m o l

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Q. The Born Haber cycle below represents the energy changes occurring at 298K when KH is formed from its elements
v :

{Δ H}_{a t o m i s a t i o n}

K = 90 kJ/mol
w :

{Δ H}_{i o n i s a t i o n}

K = 418 kJ/mol
x :

{Δ H}_{d i s s o c i a t i o n}

H = 436 kJ/mol
y :

{Δ H}_{e l e c t r o n a f f i n i t y}

H = 78 kJ/mol
z :

{Δ H}_{l a t t i c e}

KH = 710 kJ/mol

Out of v to y the most exothermic is___.

Q. The Born Haber cycle below represents the energy changes occurring at 298K when KH is formed from its elements
v :

{Δ H}_{a t o m i s a t i o n}

K = 90 kJ/mol
w :

{Δ H}_{i o n i s a t i o n}

K = 418 kJ/mol
x :

{Δ H}_{d i s s o c i a t i o n}

H = 436 kJ/mol
y :

{Δ H}_{e l e c t r o n a f f i n i t y}

H = 78 kJ/mol
z :

{Δ H}_{l a t t i c e}

KH = 710 kJ/mol

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Q. As per reaction,

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The Born Haber cycle below represents the energy changes occurring at 298K when KH is formed from its elements :
v :

{Δ H}_{a t o m i s a t i o n}

K = 90 kJ/mol
w :

{Δ H}_{i o n i s a t i o n}

K = 418 kJ/mol
x :

{Δ H}_{d i s s o c i a t i o n}

H = 436 kJ/mol
y :

{Δ H}_{e l e c t r o n a f f i n i t y}

H = 78 kJ/mol
z :

{Δ H}_{l a t t i c e}

KH = 710 kJ/mol

In terms of the letters v to z the expression for
(i)

Δ

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2 K

(s) +

H_{2}

(g)

⟶

2 K H

(s).
will be

Δ

$H =_____?

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Calculate the ΔHr of KH(s).

Born-Haber Cycle

Calculate the ${Δ H}_{r}$ of KH(s).