Question

Calculate the density ratio of liquid 1 ($\rho 1$) to that of liquid 2 ($\rho 2$) in the given pressure gauge. The ratio of $h1$ and $h2$ is $0.4$.
Gravitational acceleration ($g$) $=9.8m{s}^{-2}$

• A. $0.4$
• B. $2.5$
• C. $5$
• D. 8

Answer 1

The correct option is B $2.5$

Given:
$\frac{h_1}{h_2}=0.4$
$\frac{{\rho }_1}{{\rho }_2}=?$
We know that the beaker's liquid pressure is equal to the pipe's liquid pressure.
${\rho }_{1}g{h}_1={\rho }_{2}g{h}_2$
${\rho }_1{h}_1={\rho }_2{h}_2$
$\frac{h_1}{h_2}=\frac{{\rho }_2}{{\rho }_1}$
$0.4=\frac{{\rho }_2}{{\rho }_1}$
$\frac{{\rho }_1}{{\rho }_2}=2.5$
The density ratio of liquid 1 and liquid 2 is $2.5$