Question

Calculate the deviation suffered by a ray which is incident on a plane horizontal mirror at an angle of ${60}^o$ to the normal

• A. ${120}^o$
• B. ${90}^o$
• C. ${45}^o$
• D. ${60}^o$

Answer 1

Answer: (D)

${60}^o$


So from the figure angle of reflection is ${60}^0$, by laws of reflection hence, angle of deviation
$\delta ={180}^0-i-r={180}^0-{60}^0-{60}^0$
$\delta ={60}^0$