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Properties of Water

Calculate the...

Question

Calculate the ebullioscopic for water. The heat of vapourisation is $40.685 k J m o l^{- 1}$ .

0.512 K k g m o l^{- 1}

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1.86 K k g m o l^{- 1}

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5.12 K k g m o l^{- 1}

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3.56 K k g m o l^{- 1}

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Solution

The correct option is A $0.512 K k g m o l^{- 1}$
$K_{b} = \frac{M R T_{b} \times T_{b}}{1000 \times D H_{v}}$

$K_{b} = \frac{18 \times 8.314 \times 273 \times 273}{1000 \times 40.685 \times 1000}$

$K_{b} = \frac{20820933.108}{40.685 \times 1000000}$
$K_{b} = 0.512$ M is molecular mass of water $T_{b}$ is boiling point of water

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