Calculate the effective magnetic moment of copper ( $z = 29$ ).

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Solution

Atomic number of $C u$ is $29$ .
It has $10$ electrons in its $3 d$ sub shell.
Hence, no partially filled $3 d$ orbitals magnetic moment $= \sqrt{n (n + 2)}$
Where $n =$ number of partially filled $d$ orbitals for $C u$ $= 0$
$⟹ M a g n e t i c m o m e n t = 0$

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