Question

Calculate the electric potential difference between the outside and the inside cylinders in $V$.

Answer 1

$V=\frac{\lambda }{2\pi {\epsilon }_0}\ln \frac{R_0}{R_1}$

$\lambda$ is charge per unit length

$R_0$ outer radius

$R_i$ inner radius

$V=\frac{30\times 9\times {10}^9}{2}\ln \frac{75}{18}$

$V=\frac{30\times 9\times {10}^9}{2}\times 1.43=193\times {10}^9$volts