Calculate the electrode potential at a copper electrode dipped in a 0-1 M solution of copper sulphate at 25-C- The standard electrode potential of Cu2-Cu system is 0-34 volt at 298 K-

We know that, E_red = E_red^∘ + 0.0591nlog_10 [ion] Putting the values of E_red^∘ = 0.34 V, n = 2 and [Cu^2+] = 0.1M E_red = 0.34 + 0.05912 ...

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Calculate the electrode potential at a copper electrode dipped in a $0.1 M$ solution of copper sulphate at $25^{\circ} C$ . The standard electrode potential of $C u^{2 +} / C u$ system is $0.34 v o l t$ at $298 K$ .

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N i | N i^{2 +} | | C u^{2 +} | C u

0.76 v o l t

- 0.34 v o l t

25^{\circ} C

Z n^{2 +}

C u^{2 +}

What is the reduction electrode potential (in volts) of copper electrode when [ $C u^{2 +}$ ]=0.01M in a solution at $25^{0} C$ ?

(E0 of $C u^{2 +} / C u$ electrode is +0.34)

C u | C u S O_{4} a = 0.1 | | C u S O_{4} x | C u

- 0.03 V

25^{\circ} C

0.01 M Z n S O_{4}

25^{\circ} C

Z n / Z n^{+}

0.763

25^{\circ} C

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