You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Chemistry

Covalent Bond vs Ionic Bond

Calculate the...

Question

Calculate the electron affinity of oxygen atom in gaining two electrons to give the oxide ion $O^{2 -}$ from the following data.
Standard heat of formation of $M g O_{(s)} = - 600 k J m o l^{- 1}$
Lattice energy of $M g O_{(s)} = - 3860 k J m o l^{- 1}$
lonization energy of $M g_{(g)}$ to give $M g^{2 +}$ = +2170 $k J m o l^{- 1}$
Dissociation energy of $O_{2 (g)}$ = +494 $k J m o l^{- 1}$
Heat of sublimation of $M g_{(s)}$ = +150 $k J m o l^{- 1}$

- 493 k J m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 493 k J m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 693 k J m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 693 k J m o l^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $+ 693 k J m o l^{- 1}$
Given, $Δ_{f} H_{M g O} = - 600 k J m o l^{- 1}$
$M g_{(s)} \to M g_{(g)} Δ_{s} H = + 150 k J m o l^{- 1}$
$M g_{(g)} \to M g_{(g)}^{2 +} I . E . = + 2170 k J m o l^{- 1}$
$\frac{1}{2} O_{2_{(} g)} \to O_{(g)} B . E . = + 494 k J m o l^{- 1}$ $Lattice energy of M g O_{(s)} = - 3860 k J m o l^{- 1}$
$Δ_{f} H_{M g O} = Δ_{s} H + I . E . + \frac{1}{2} B . E . + E . A . + Lattice energy$
$- 600 = 150 + 2170 + 247 + E . A . - 3860$
$E . A . = - 600 - 150 - 2170 - 247 + 3860$
$∴ E A = + 693 k J m o l^{- 1}$

Suggest Corrections

Similar questions

Q. Calculate the electron affinity of oxygen atom in gaining two electrons to give the oxide ion

O^{- 2}

from the following data.
Standard heat of formation of

M g O_{(s)} = - 600 k J m o l^{- 1}

Lattice energy of

M g O_{(s)} = - 3860 k J m o l^{- 1}

lonization energy of

M g_{(g)}

to give

M g^{+ 2}

is +2170

k J m o l^{- 1}

Dissociation energy of

O_{2 (g)}

is +494

k J m o l^{- 1}

Heat of sublimation of

M g_{(s)}

is +150

k J m o l^{- 1}

Q. Use the following data to calculate second electron affinity of oxygen for the process

O^{-} (g) + e^{-} (g) \to O^{2 -} (g)

.
Heat of sublimation of

M g (s) = 147.7 kJ/mol

Ionisation energy of

M g (g)

to form

M g^{2 +} (g) = 2189 kJ/mol

Bond dissociation energy for

O_{2}

= 498.4 kJ/mol

First electron affinity of

O (g) = - 141 kJ/mol

Heat formation of

M g O (s) = - 601.7 kJ/mol

lattice energy of

M g O = - 3791 kJ/mol

Q. Use the following data to calculate second electron affinity of oxygen for the process

O^{-} (g) + e^{-} (g) \to O^{2 -} (g)

.
Heat of sublimation of

M g (s) = 147.7 k J / m o l

Ionisation energy of

M g (g)

to form

M g^{2 +} (g) = 2189 k J / m o l

Bond dissociation energy for

O_{2}

= 498.4 k J / m o l

First electron affinity of

O (g) = - 141 k J / m o l

Heat formation of

M g O (s) = - 601.7 k J / m o l

lattice energy of

M g O = - 3791 k J / m o l

Q. Use the following data to calculate the lattice energy of cesium oxide.
Enthalpy of formation of cesium oxide =

- 233 k J / m o l

Enthalpy of sublimation of

C s = + 78 k J / m o l

First ionization energy of

C s = + 375 k J / m o l

Enthalpy of dissociation of

O_{2} (g) = 494 k J / m o l

O_{2}

molecules
First electron affinity of

O = - 141 k J / m o l

of O atoms
Second electron affinity of

O = + 845 k J / m o l

O^{-}

ions

Q. Use the following data to calculate the lattice energy of caesium oxide.
Enthalpy of formation of caesium oxide =

- 233 k J m o l^{- 1}

Enthalpy of sublimation of

C s = + 78 k J m o l^{- 1}

First ionization energy of

C s = + 375 k J m o l^{- 1}

Enthalpy of dissociation of

O_{2} (g) = 494 k J m o l^{- 1} o f O_{2} m o l e c u l e s

First electron affinity of

O = - 141 k J m o l^{- 1} o f O a t o m s

Second electron affinity of

O = + 845 k J m o l^{- 1} o f O^{1 -} i o n s

Join BYJU'S Learning Program

Explore more

Covalent Bond vs Ionic Bond

Standard XI Chemistry

Join BYJU'S Learning Program