Calculate the electron gain enthalpy of fluorine atom using the following data- All the values are in kJ mol-1 at 25oC- - HdissF2 - 160- -fHNaFs - -571- I-E- -Nag- - 494- - Hvap-Nas- - 101- Lattice enthalpy of NaFs - 894-Also- make Born - Haber-s cycle-

Lattice energy =Δ H_f+Δ H_vap(Na) 12Δ H_diss IE EA EA= 571+101 12(160) 494 894 470 80 494 894 EA= 1938 KJ mol^ 1 . ...

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Covalent Bond

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Calculate the electron gain enthalpy of fluorine atom using the following data.
All the values are in $k J m o l^{- 1}$ at $25^{o} C$ . $Δ H_{d i s s} (F_{2}) = 160, Δ_{f} H (N a F (s)) = - 571$ , I.E. $[N a (g)] = 494, Δ H_{v a p} [N a (s)] = 101$ . Lattice enthalpy of $N a F (s) = 894$ .
Also, make Born - Haber's cycle.

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k J

{m o l}^{- 1}

25^{o} C

Δ H_{d i s s} (F_{2}) = 160

Δ H_{r}^{o}

N a F (s)) = - 571; I . E

[N a (g)] = 494, Δ H_{v a p} [N a (s)] = 101

N a F (s) = - 894

N a^{+}

N a (g)

495.8 k J m o l^{- 1}

- 325.0 k J m o l^{- 1}

N a B r

- 728.4 k J m o l^{- 1}

N a B r

\times 10^{- 1} k J m o l^{- 1}

K C l

K = 89 k J m o l^{- 1}

C l_{2} = 244 k J m o l^{- 1}

K = 425 k J m o l^{- 1}

C l = - 355 k J m o l^{- 1}

K C l = - 438 k J m o l^{- 1}

K C l

K = 89 k J m o l^{- 1}

C l_{2} = 244 k J m o l^{- 1}

K = 425 k J m o l^{- 1}

C l = - 355 k J m o l^{- 1}

K C l = - 438 k J m o l^{- 1}

N a^{+}

{I.E.}_{1}

N a = 5.1 e V

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