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Question

Calculate the electronegativity of chlorine from the given data: bond energy of ClF bond (61 kcal mol1), FF(38 kcal mol1) and ClCl bond (58 kcal mol1) and electronegativity of fluorine is 4.0.

A
2.33
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B
3.22
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C
3.33
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D
2.67
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Solution

The correct option is B 3.22
According to Pauling's Scale:
Δ = χFχCl = 0.208×EClF(EFF×EClCl)
where, EClF = Bond energy of ClF bond (kcal/mol)
EFF = Bond energy of FF bond (kcal/mol)
EClCl = Bond energy of ClCl bond (kcal/mol)
χF = Electronegativity of F
χCl = Electronegativity of Cl
χFχCl = 0.208×6158×38)
χFχCl = 0.208×14.05
χCl = χF0.208×14.05
χCl = 4.00.78
χCl = 3.22

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