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Question
Calculate the electronegativity of fluorine from the following data:
Bond energy of H-H bond EH−H=104.2 kcal mol−1
Bond energy of F-F bondEF−F=36.6 kcal mol−1
Bond energy of H-F bond EH−F=134.6 kcal mol−l
Electronegativity of Hydrogen XH=2.1.
Calculate the electronegativity of fluorine from the following data:
Bond energy of H-H bond EH−H=104.2 kcal mol−1
Bond energy of F-F bondEF−F=36.6 kcal mol−1
Bond energy of H-F bond EH−F=134.6 kcal mol−l
Electronegativity of Hydrogen XH=2.1.
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Solution
The correct option is A 3.87
Let the electronegativity of fluorine be XF. Applying Pauling equation,
XF−XH=0.208[EH−F −(EF−F ×EH−H)0.5]0.5
In this equation, dissociation energies are taken in kcal mol−1
XF−2.1=0.208[134.6 −(104.2 ×36.6)0.5]0.5
XF = 3.87
Let the electronegativity of fluorine be XF. Applying Pauling equation,
XF−XH=0.208[EH−F −(EF−F ×EH−H)0.5]0.5
In this equation, dissociation energies are taken in kcal mol−1
XF−2.1=0.208[134.6 −(104.2 ×36.6)0.5]0.5
XF = 3.87
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