Calculate the emf and - Go for the cell reaction at 25oC- Zns - 0-1 MZn2-aq - 0-01 MCd2-aq - CdsGiven Eo Zn2- -Zn - - 0-763 and Eo Cd2-Cd - -0-403V-

Zn ^ 2+ +2 e ^ → Zn; E _ Zn ^ 2+ /Zn ^ 0 = 0.763 V Cd ^ 2+ +2 e ^ → Cd; E _ Cd ^ 2+ /Cd ^ 0 = 0.403 V Cell reaction: Cd ^ 2+ +Zn→ Cd+ Zn ^ ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

EMF

Calculate the...

Question

Calculate the emf and $Δ G^{o}$ for the cell reaction at $25^{o}$ C:
$Z n (s) | Z n_{a q}^{2 +} (0.1 M) | C d_{a q}^{2 +} (0.01 M) | C d_{(s)}$
Given $E^{o} Z n^{2 +} / Z n = - 0.763$ and $E^{o} C d^{2 +} / C d = - 0.403 V .$

Open in App

Solution

Suggest Corrections

Similar questions

C d^{2 +} (a q) + Z n (s) \to Z n^{2 +} (a q) + C d (s)

Δ_{r} G^{o}

Z n_{(s)} + A g_{2} O_{(s)} + H_{2} O_{(l)} \to Z n_{(a q)}^{2 +} + 2 A g_{(s)} + 2 O H_{(a q)}^{-}

[E_{A g_{2} O / A g}^{o} = 0.344 V, E_{Z n^{2 +} / Z n}^{o} = - 0.76 V]

C u I (s) + e^{-} \to C u (s) + I^{-};

E_{C u^{+} / C u}^{o} = - 0.16 V

Z n^{2 +} (a q) + 2 e^{-} \to Z n (s);

E_{Z n^{2 +} / Z n}^{o} = - 0.76 V

Z n (s) + 2 H^{+} (aq) \to Z n^{2 +} (0.1 M) + H_{2} (g, 1 bar)

0.28 V

25^{\circ} C

E_{Z n^{2 +} | Z n}^{\circ} = - 0.763 V

E_{c e l l} = 0.2905 V

Z n (s) + F e^{2 +} (a q) 0.01 M \to Z n^{2 +} 0.1 M (a q) + F e (s)

Join BYJU'S Learning Program