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Question

Calculate the emf and ΔGo for the cell reaction at 25oC:
Zn(s)|Zn2+aq(0.1M)|Cd2+aq(0.01M)|Cd(s)
Given EoZn2+/Zn=0.763 and EoCd2+/Cd=0.403V.

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Solution

Zn2++2eZn; E0Zn2+/Zn=0.763VCd2++2eCd; E0Cd2+/Cd=0.403 V
Cell reaction:
Cd2++ZnCd+Zn2+
emf of the cell is, E0cell=0.7630.403=0.360 VΔG0=nFE0cell
where, n=2 and F=faraday constant = 96485 C/mol
ΔG0=2×96485×0.36ΔG0=69.5 kJ

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