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Byju's Answer
Standard XII
Chemistry
Electrochemical Cells, Galvanic Cells
Calculate the...
Question
Calculate the EMF of a Daniel cell when the concentration of
Z
n
S
O
4
and
C
u
S
O
4
are 0.001 M and 0.1 respectively. The standard potential of the cell is 1.1 V.
Open in App
Solution
Z
n
+
C
u
2
+
→
Z
n
2
+
+
C
u
Nernst equation:
E
c
e
l
l
=
E
0
−
0.059
n
l
o
g
⎡
⎢ ⎢
⎣
(
Z
n
2
+
)
(
C
u
2
+
)
⎤
⎥ ⎥
⎦
E
c
e
l
l
=
1.1
−
0.059
2
l
o
g
[
0.001
0.1
]
E
c
e
l
l
=
1.1
−
0.059
2
×
(
−
2
)
=
1.159
V
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0
Similar questions
Q.
Calculate the EMF of a Danial cell when the concentration of
Z
n
S
O
4
and
C
u
S
O
4
are
0.001
M and
0.1
M respectively. The standard EMF of the cell is
1.1
V.
Q.
The emf of a Daniel cell at 298 K is
E
1
concentration of
Z
n
S
O
4
is 0.1 M and that
C
u
S
O
4
is 0.01 M, the emf changed to
E
2
.What is the relationship between
E
1
and
E
2
Q.
The emf of Daniell cell at
298
K
is
E
1
Z
n
|
Z
n
S
O
4
(
0.01
M
)
|
|
C
u
S
O
4
(
1.0
M
)
|
C
u
When the concentration of
Z
n
S
O
4
is
1.0
M
and that of
C
u
S
O
4
is
0.01
M
, the emf changed to
E
2
What is the relation between
E
1
and
E
2
?
Q.
Calculate the emf of the cell.
Z
n
|
Z
n
2
+
(
0.001
M
)
|
|
C
u
2
+
(
0.1
M
)
|
C
u
The standard potential of
C
u
/
C
u
2
+
half-cell is +0.34 and
Z
n
/
Z
n
2
+
is -0.76 V.
Q.
In the electrochemical cell:
Z
n
|
Z
n
S
O
4
(
0.01
M
)
∥
C
u
S
O
4
(
1.0
M
)
|
C
u
, the emf of a Daniell cell at
298
K
is
E
1
. When the concentration of
Z
n
S
O
4
is
1.0
M
and that of
C
u
S
O
4
is
0.01
M
, the emf changed to
E
2
. What is the relations between
E
1
and
E
2
?
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