Question

Calculate the EMF of a Daniel cell when the concentration of $Zn{SO}_4$ and $Cu{SO}_4$ are 0.001 M and 0.1 respectively. The standard potential of the cell is 1.1 V.

Answer 1

$Zn+{Cu}^{2+}\to {Zn}^{2+}+Cu$

Nernst equation:

$E_{cell}=E^0-\frac{0.059}{n}log\left[\frac{\left({Zn}^{2+}\right)}{\left({Cu}^{2+}\right)}\right]$

$E_{cell}=1.1-\frac{0.059}{2}log\left[\frac{0.001}{0.1}\right]$

$E_{cell}=1.1-\frac{0.059}{2}\times (-2)=1.159V$