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Question

Calculate the emf of the following cell at 25C : Ag(s)|Ag+(103M)||Cu2+(101M)|Cu(s)
Given Ecell=+0.46 V and log 10n=n.

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Solution

For the given cell, the redox reaction is
2Ag(s)+Cu2+(aq)2Ag+(aq)+Cu(s)
n=2
Ecell=Ecell0.0591nlog[Ag+]2[Cu2+]
=0.460.05912log(103)2101
=0.460.02955 log 105
=0.460.02955×(5)
=0.46+0.14775=0.60775 V.

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