Calculate the emf of the following cell at 298 K.
Zn(s)∣Zn2+(aq, 0.1 M)∥Ag+(aq, 0.01 M)∣ Ag(s)
E0Zn2+/Zn = −0.76 V
E0Ag+/Ag =+0.80 V
emf of the following cell at 298 K in V is x ×10−2
The value of x is____. (Rounded off to the nearest integer)