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Question

Calculate the energy in kilocalorie per mole of photons of an electromagnetic radiation having a wavelength of 7600 A.

A
33.56
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B
37.56
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C
47.35
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D
42.35
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Solution

The correct option is B 37.56
Given,
wavelength (λ)=7600 A=7600×108 cm .
Speed of light (c)=3×1010 cm s1
Therefore frequency, v=cλ=3×10107600×108=3.947×1014 s1

Energy of one photon =hv
=6.62×1034×3.947×1014 J
=2.61×1019 J
Energy of one mole of photons
=2.61×1019×6.023×1023
=15.72×104 J=157.2 kJ

Energy of one mole of photons in kilocalorie =157.24.185=37.56 kcal per mol
[1 kcal=4.185 kJ]

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