Calculate the energy in the reaction 2 1 1 H - 2 0 1 n - 2 4 HeGiven- H-1-00813 amu- n-1-00897 amu and He-4-00388 amu

Loss of mass in the given nuclear reaction = 2× Mass of Hydrogen + 2× Mass of n Mass of Helium =2( 1.00813+1.00897 ) 4.00388 =0.030 ...

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Nuclear Fission

Calculate the...

Question

Calculate the energy in the reaction
$2_{1}^{1} H + 2_{0}^{1} n \to$ $_{2}^{4} H e$
Given, $H = 1.00813 a m u$ , $n = 1.00897 a m u$ and $H e = 4.00388 a m u$

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_{3}^{6} L i +_{0}^{1} n ⟶_{2}^{4} H e +_{1}^{3} H

_{3}^{6} L i = 6.015126 a m u,_{2}^{4} H e = 4.002604 a m u

_{1}^{3} H = 3.016049 a m u,_{0}^{1} n = 1.008665 a m u

_{3}^{7} L i +_{1}^{1} H \to 2 [_{2}^{4} H e]

_{3}^{7} L i,_{1}^{1} H

_{2}^{4} H e

7.018, 1.008

4.004 a m u

_{1}^{2} H +_{1}^{3} H ⟶

_{2}^{4} H e +_{0}^{1} n

_{1}^{2} H = 2.014

a m u

_{1}^{3} H = 3.016

a m u

_{2}^{4} H e = 4.004

a m u

_{0}^{1} n = 1.008

a m u

_{1}^{2} H +_{1}^{3} H ⟶

_{2}^{4} H e +_{0}^{1} n

_{1}^{2} H

_{1}^{3} H

_{2}^{4} H e

a

b

c

_{7}^{14} N +_{2}^{4} H e ⟶

_{8}^{17} O +_{1}^{1} H

_{4}^{9} B e +_{1}^{1} H ⟶

_{3}^{9} L i +_{2}^{4} H e

_{12}^{24} M g +_{2}^{4} H e ⟶

_{14}^{27} S i +_{0}^{1} n

_{5}^{10} B +_{2}^{4} H e ⟶

_{7}^{13} N +_{0}^{1} n

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