Question

Calculate the energy of an electron present in Bohr's second orbit of hydrogen atom in $kJmo{l}^{-1}$.

• A. $-564kJ$
• B. $-324kJ$
• C. $-328kJ$
• D. $-632kJ$

Answer 1

The correct option is C $-328kJ$

Energy of an electron in a orbit $=E=-1312\frac{Z^2}{n^2}kJmo{l}^{-1}$

Therefore, energy of electron in second orbit of H-atom $=E=-1312\left(\frac{1^2}{2^2}\right)$ = $-328kJmo{l}^{-1}$