Calculate the energy of radiation emitted for the electronic transition from infinity (∞) to ground state of an H-atom.
Rydberg constant = 1.09678×107m−1
A
2.18×10−20 J
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B
1.81×10−20J
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C
2.18×10−18J
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D
1.81×10−18J
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Solution
The correct option is C2.18×10−18J Using the formula, 1λ=RH[1n21−1n22]
Where λ = wavelength of the radiation n1=1andn2=∞ 1λ=1.09678×107m−1[112−1∞2]=1.09678×107m−1λ=9.11×10−8mE=hcλ=6.626×10−34×3×1089.11×10−8=2.18×10−18J