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Question

Calculate the energy of radiation emitted for the electronic transition from infinity () to ground state of an H-atom.
Rydberg constant = 1.09678×107m1

A
2.18×1020 J
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B
1.81×1020J
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C
2.18×1018J
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D
1.81×1018J
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Solution

The correct option is C 2.18×1018J
Using the formula,
1λ=RH[1n211n22]
Where λ = wavelength of the radiation
n1=1 and n2=
1λ=1.09678×107m1[11212]=1.09678×107m1λ=9.11×108mE=hcλ=6.626×1034×3×1089.11×108=2.18×1018J

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