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Byju's Answer
Standard XII
Physics
Chain Reaction of Uranium
Calculate the...
Question
Calculate the energy released in
m
e
V
in the following nuclear reaction:
298
92
U
⟶
234
90
T
H
+
4
2
H
e
+
Q
[Mass of
298
92
U
=
238.05079
u
Mass of
234
90
T
H
=
234.043630
u
]
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Solution
Given:
Mass of
298
92
U
=
238.05079
u
, Mass of
234
90
T
H
=
234.043630
u
Mass Defect = Mass of uranium - Mass of thorium - Mass of helium
Mass defect
=
238.05079
u
−
234.043630
u
−
4.002600
u
=
0.004564
u
Now,
1
u
releases
931.5
M
e
V
/
c
2
energy
⇒
Energy released by
0.004564
u
=
(
0.00456
×
931.5
)
M
e
V
/
c
2
=
4.24764
M
e
V
/
c
2
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