wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the energy released when an electron annihilates a positron.

Open in App
Solution

The equation is given by: 1β0++1β0hv+hv
Δm=2×9×1031
=18×1031kg
ΔE=Δmc2
=18×1031×(3×108)2
=18×1031×9×1016
=162×1015
=1.62×1013J
=1.62×10131.6×1019eV
=1.0125×106eV
=1.0125MeV.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mass - Energy Equivalence
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon