MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Energy Levels

Calculate the...

Question

Calculate the energy released when an electron makes transition from an excited energy level to the ground state of the hydrogen like atom. Given that ionization energy and ground state energy are 25 eV and -16 eV respectively.

A

9 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

11 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

16 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

25 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E

41 eV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is E 41 eV
Energy of electron in excited state= $25 e V$
Energy of electron in ground state= $- 16 e V$
The energy released would be the difference in the initial and final energy level
$= 25 e V - (- 16 e V)$
$= 41 e V$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A hydrogen-like atom of atomic number

Z

is in an excited state of quantum number

2 n

. It can emit a maximum energy photon of

204 e V

. If it makes a transition to quantum state

n

, a photon of energy

40.8 e V

is emitted. Find

n, Z

and the ground state energy (in eV) for this atom. Also, calculate the minimum energy (in eV) that can be emitted by this atom during de-excitation. Ground state energy of hydrogen atom is

- 13.6 e V

.

Q. The ground state energy of hydrogen atom is

- 13.6

eV. If an electron makes a transition from an energy level

- 1.51

- 3.4

eV, then calculate the wavelength of the spectral line emitted and name the series of hydrogen spectrum to which it belongs.

Q. The ground state energy of hydrogen atom is

- 13.6 e V

. If an electron make a transition from an energy level

- 0.85 e V

- 1.51 e V

, calculate the wavelength of the spectral line emitted. To which series of hydrogen spectrum does this wavelength belong?

Q. The ionization energy of hydrogen is

13.6 e V

. The energy of the photon released when an electron jumps from the first excited state

(n = 2)

to the ground state of a hydrogen atom is:

Q. Calculate the energy gap between the first energy state and the third excited state of a hydrogen like atom, given that the energy of the first excited state is -3.4 eV.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Energy Levels

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon