The correct option is
D none of these
Determination of number of moles of H gas,
N=PVRT=1×10.082×298=0.0409
The concerned reaction is H2→2H, deltaH=436 Kj/mol
Energy required to bring 0.0409 moles of H gas to atomic state =436×0.0409=17.83 kJ
1 mole of H2 gas has 6.022×1023 molecules
Since, 1 molecule of H2 gas has 2H atom =6.022×1023×0.0409
=2×6.022×1023×0.0409=4.92×1022 atoms of H
E=13.6(1n21−1n22)eV=13.6×(11−14)=13.6×34=10.2eV
=1.632×10−21Kj
Therefore energy required to excited 4.92×1022 electrons
=1.632×10−21×4.92×10−22Kj
=8.03×10=80.3Kj
Therefore total energy required =17.83+80.3=98.17 kJ