Calculate the energy transferred by a $5 A$ current flowing through a resistor of $20 o h m s$ for $30$ minutes.

25

k W h

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50

k W h

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2.5 \times 10^{- 2} k W h

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5 \times 10^{- 2} k W h

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Solution

The correct option is A $2.5 \times 10^{- 2} k W h$
$E = I^{2} R t$
$= 5^{2} \times 2 \times \frac{1}{2}$
$= 2.5 \times 10^{- 2} k W h$

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Calculate the energy transferred by a 5A current flowing through a resistor of 20 ohms for 30 minutes.

The correct option is A 2.5×10−2kWhE=I2Rt=52×2×12=2.5×10−2kWh

Calculate the energy transferred by a $5 A$ current flowing through a resistor of $20 o h m s$ for $30$ minutes.

The correct option is A $2.5 \times 10^{- 2} k W h$
$E = I^{2} R t$
$= 5^{2} \times 2 \times \frac{1}{2}$
$= 2.5 \times 10^{- 2} k W h$